Natural Numbers Between 1 and 100, Represented as Sum of Three Cubes

It came to me as a shock that the first page of Google failed me when I wanted to show the following information at a party, so I wanted to post my own list.

It is compiled from Internet News Articles, and Wikipedia.

Note that in the case of a non-unique solution, preferably, the result with the smallest biggest term was taken. This claim is yet to be fully verified.

1 = (-1)³ + 1³ + 1³

2 = 7³ + (-5)³ + (-6)³

3 = 1³ + 1³ + 1³

6 = (-1)³ + (-1)³ + 2³

7 = 104³ + 32³ + (-105)³

8 = (-1)³ + 1³ + 2³

9 = 217³ + (-52)³ + (-216)³

10 = 1³ + 1³ + 2³

11 = (-2)³ + (-2)³ + 3³

12 = 7³ + 10³ + (-11)³

15 = (-1)³ + 2³ + 2³

16 = (-511)³ + (-1609)³ + 1626³

17 = 1³ + 2³ + 2³

18 = (-1)³ + (-2)³ + 3³

19 = 19³ + (-14)³ + (-16)³

20 = 1³ + (-2)³ + 3³

21 = (-11)³ + (-14)³ + 16³

24 = 2³ + 2³ + 2³

25 = (-1)³ + (-1)³ + 3³

26 = 297³ + 161³ + (-312)³

27 = (-1)³ + 1³ + 3³

28 = 14³ + 13³ + (-17)³

29 = 1³ + 1³ + 3³

30 = (-283059965)³ + (-2218888517)³ + 2220422932³

33 = 8866128975287528³ + (-8778405442862239)³ + (-2736111468807040)³

34 = (-1)³ + 2³ + 3³

35 = 14³ + (-8)³ + (-13)³

36 = 1³ + 2³ + 3³

37 = 50³ + 37³ + (-56)³

38 = 1³ + (-3)³ + 4³

39 = 117367³ + 134476³ + (-159380)³

42 = (-80538738812075974)³ + 80435758145817515³ + 12602123297335631³

43 = 2³ + 2³ + 3³

44 = (-5)³ + (-7)³ + 8³

45 = 2³ + (-3)³ + 4³

46 = (-2)³ + 3³ + 3³

47 = 6³ + 7³ + (-8)³

48 = (-23)³ + (-26)³ + 31³

51 = 602³ + 659³ + (-796)³

52 = 23961292454³ + 60702901317³ + (-61922712865)³

53 = (-1)³ + 3³ + 3³

54 = (-7)³ + (-11)³ + 12³

55 = 1³ + 3³ + 3³

56 = (-11)³ + (-21)³ + 22³

57 = 1³ + (-2)³ + 4³

60 = (-1)³ + (-4)³ + 5³

61 = 845³ + 668³ + (-966)³

62 = 3³ + 3³ + 2³

63 = 7³ + (-4)³ + (-6)³

64 = (-1)³ + 1³ + 4³

65 = 91³ + 85³ + (-111)³

66 = 1³ + 1³ + 4³

69 = 2³ + (-4)³ + 5³

70 = 11³ + 20³ + (-21)³

71 = (-1)³ + 2³ + 4³

72 = 7³ + 9³ + (-10)³

73 = 1³ + 2³ + 4³

74 = (-284650292555885)³ + (66229832190556)³ + (283450105697727)³

75 = 4381159³ + 435203083³ + (-435203231)³

78 = 26³ + 53³ + (-55)³

79 = (-19)³ + (-33)³ + 35³

80 = 69241³ + 103532³ + (-112969)³

81 = 3³ + 3³ + 3³

82 = (-11)³ + (-11)³ + 14³

83 = (-2)³ + 3³ + 4³

84 = (-8241191)³ + (-41531726)³ + 41639611³

87 = (-1972)³ + (-4126)³ + 4271³

88 = 3³ + (-4)³ + 5³

89 = 6³ + 6³ + (-7)³

90 = (-1)³ + 3³ + 4³

91 = 364³ + 192³ + (-381)³

92 = 1³ + 3³ + 4³

93 = (-5)³ + (-5)³ + 7³

96 = 10853³ + 13139³ + (-15250)³

97 = (-1)³ + (-3)³ + 5³

98 = 14³ + 9³ + (-15)³

99 = 2³ + 3³ + 4³

100 = 7³ + (-3)³ + (-6)³

Numbers that are 4 or 5 (mod 9) cannot be written as three cubes because all natural numbers’ cubes can only be 0, 1 or 8 (mod 9), and with three of them we cannot make a 4 nor a 5.

EDIT:

I think that because I’ve opted out of AMP and Ad services on this site, I still won’t make it to first page of Google, even when searching the exact title of this page.

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